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  • Explanation of logomatic IRQ frequency asked

    I tried to understand the frequency working of the logging but do not understand how it calculates the counter value for IRQ.

    The T0MR0 = 58982400 / freq; should match the clock speed of 12 mHz at a frequency of 1Hz. It is 4,9 times bigger. I tested the frequency and it really works at 20Hz.

    Does anyone know how it works?

    This is the timer setup code:

    void mode_2(void)
    {
    rprintf(“MODE 2\n\r”);
    enableIRQ();
    // Timer0 interrupt is an IRQ interrupt
    VICIntSelect amp= ~0×00000010;
    // Enable Timer0 interrupt
    VICIntEnable |= 0×00000010;
    // Use slot 2 for UART0 interrupt
    VICVectCntl2 = 0×24;
    // Set the address of ISR for slot 1
    VICVectAddr2 = (unsigned int)MODE2ISR;

    T0TCR = 0×00000002; // Reset counter and prescaler
    T0MCR = 0×00000003; // On match reset the counter and generate interrupt
    T0MR0 = 58982400 / freq;

    T0PR = 0×00000000; // Disable preset register

    T0TCR = 0×00000001; // enable timer

    stringSize = 512;
    mode_action();
    }

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